2000x-20x^2=0

Solution for 2000x-20x^2=0 equation:

2000x-20x^2=0

a = -20; b = 2000; c = 0;
Δ = b2-4ac
Δ = 20002-4·(-20)·0
Δ = 4000000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4000000}=2000$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2000)-2000}{2*-20}=\frac{-4000}{-40}
=+100
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2000)+2000}{2*-20}=\frac{0}{-40}
=0
$